SMO 2019 Junior Rd 2 Namelist
SMO 2019 Junior Rd 2 Questions
SMO 2019 Junior Questions
SMO 2019 (Junior Section) Answers
1. E
2. E
3. E
4. C
5. D
6. 360
7. 120
8. 9
9. 99
10. 14
11. 8
12. 12
13. 48
14. 201
15. 50
16. 8
17. 1010
18. 86
19. 6
20. 13
21. 73
22. 8
23. 12
24. 105
25. 20
How would u rate this year’s smo
ReplyDeleteHarder or easier than 2018
Will 12 get me bronze or silver
I honestly don't know what you will attain but I personally considered it to be slightly more perplexing. I established way too many careless mistakes I attained 8 correct answers, could have procured 21 correct answers if they weren't 1 digit off. : C
DeleteSo what did u get?
DeleteAbout the same difficulty. 12 should be a bronze
ReplyDeleteHey I got 3 will I get into round 2?
ReplyDeleteU r meme
DeleteIm not sure i got 2.5 marks
DeleteWill I get into round 2 with 13
ReplyDeleteWhat do u think is this yr cutoff point
ReplyDeleteHey, would 14 get me a silver? Also, what do you think the cut off is going to be this year?
ReplyDeleteI got 19, will i get gold or silver?
ReplyDeletehey what will 5 get me
ReplyDeleteIs 20 enough to get gold
ReplyDeleteI believe that is good.
DeleteGold definitely.
Deleteis 0/25 able to get silver?
ReplyDeleteWould 15 or 16 get me to round 2?
ReplyDeleteThe cutoff point is 16 last year.
ReplyDeletewould 5 get me an honourable mention
ReplyDeletewould 15 be enough for round 2?
ReplyDeleteso many carelesssssssssssssssss
hey i got 7 what will i get
ReplyDeleteQ12 should be 11
ReplyDeleteA is $8 with 4 toys
B is $3 with 3 toys
A and B have the same amount of toys.
DeleteThey said that there were same amount of toys in A and B
ReplyDeleteIs 8 enough to get bronze or go to second round?
ReplyDeleteWould 11 get me a bronze?
ReplyDeleteWhen do the results come out? Would 18 be enough to get into the next round?
ReplyDeleteHow did you get the answers?
ReplyDeleteI got 16 or 17. Can I get into the next round? Can I get a silver?
ReplyDeleteQn 10 answer shld be 15 right?
ReplyDelete15*2+3*4+7*5=77
15+3+7=25
More than 3 gifts for each type so you have to buy at least four $4 gifts.. I read the question wrongly too hehe
Deleteis 6 enough for honourable mention?
ReplyDeleteWhen will the result be posted?
ReplyDeleteQ10: can't have only 3 $4 gifts
ReplyDeleteisn't the answer to q6 540
ReplyDeleteq6 is 360 as the sum of interior angles in the pentagon is 540 degrees, which is 180*5 (5 triangles) minus the 10 unknown angles, which will result in 360 degrees
ReplyDeletewill 17/25 get me into r2
ReplyDeleteCan anyone help to solve question 20? Thanks
ReplyDeleteMay I ask if I can get a Bronze with 9? Thank you! (I'm so desperate to get a Bronze)
ReplyDelete
ReplyDeleteQuestion 20
Y= (x^2 + 2^2)^1/2 + ((12-x)^2 + 3^2)^1/2
Minimum Y = ((2 + 3)^2 + (12-x+x)^2)^1/2
= (5^2 + 12^2)^1/2
= 13
Will 9 give me bronze or honourable mention? And shouldnt q2 be c, last year smo junior paper 2nd question is the same as this year second question? Thank you for answering
ReplyDeleteThe question is not the same its like 1 word different
DeleteIs the SMO 2019 result list out?
ReplyDeleteThe smo results are out!
ReplyDeleteWhat is the cut-off mark to the 2nd round in this year?
ReplyDeleteI got 15/16 but did not get to the 2nd round. What is the cut off point this year?
ReplyDeleteThe cut off was 14.....
ReplyDeleteHow do you do question 24?
ReplyDeleteI just took the SMO Round 2. It was very hard. Can someone help me crack question 2 and 4 on the Round 2 exam! Thanks in advance.
ReplyDelete@Sean
ReplyDeleteFor question 2, the answer is that he would not be able to separate it into 315 piles but my friends and i had different workings. my
working was that 315 = 256 + 32 + 16 + 8 + 2 + 1. But since any pile would not be able to begin with one as 1 is an odd number, he cannot divide it into 315 piles
What were your answers for Q1, 3, and 5.
I was not able to do Q4 either.
@Ava
ReplyDeleteMy solution for Q1 involves coordinate geometry, so I probably got deducted some points. For 3, I just checked n>m and n<m and n=m using inequalities. got (5,3), (3,5) and (1,1) as my answers. For q5 I got n^2.
I got it! The following is the solutions for Q4:
ReplyDelete(2)^1/2*a^3 + 3/(ab - b^2) is larger or equal to (2)^1/2*a^3 + 3/(a^2/4)=
(2)^1/2*a^3 + 12/a^2 = ((2)^1/2)/2*a^3 + ((2)^1/2)/2*a^3 + 4/a^2 + 4/a^2 + 4/a^2 is larger or equal to five times the fifth root of each term in the preceding sum, which is equal to 5(32)^1/5 = 10. Thus, (2)^1/2*a^3 + 3/(ab - b^2) is always larger or equal to 10. Equality occurs when all the terms are equal, which is the solution to ((2)^1/2)/2*a^3 = 4/a^2 which is a = root 2. Because b must be so that the original sum is as low as possible, b = a/2 = (root 2)/2 = 1/(root 2).
Q1: the centroid G of triangle ABC is also the orthocentre of triangle ACE. Thus, the line GE meets AC at 90 degrees, so you can deduce that GE // BC. Therefore, using similar triangles, AE : EB = AG : GD = 2 : 1
ReplyDeleteare results out?
ReplyDeleteResults are out!!!!
ReplyDeleteI cannot find the results here: http://sms.math.nus.edu.sg/Competitions/Results.aspx
ReplyDeleteWhere is it?
My solution for Q2 at round 2:
ReplyDeleteTo be divisible to unit (one marble) piles, the number of marble in a pile should be a power of 2, e.g. 2, 4, 8, 16, etc.
Since initially, all three piles have uneven number of marbles, in the first step we can only merge two of them. There three ways to do that, e.g. 81+115 and 119, 81 and 115+119, 81 + 119 and 115.
In each way, the two piles obtained after the first step have a common divisor differ from a power of 2 (2^n). For example, in the first way, we have 196 and 119, and common divisor is 7.
What ever we will do (merge or divide by 2), the number of marbles in piles will be a multiplication of this common divisor (7 in previous example), what is indivisible into units piles.
are round 1 results out(hm,bronze,silver,etc)
ReplyDeleteomg is this even sec 1???so hard leh
ReplyDeletei just passed bruh that sucks
ReplyDeleteThat is shitty low quality of question and answer bruh
ReplyDeleteThe thing don't even give steps to answer lol
Proof
May I know for the first round, how many marks will lead to bronze silver and gold
ReplyDeleteCan somebody tell me the solutions for all the round 2 questions? Thanks in advance!
ReplyDelete