SMO 2011 Open Special Round Participants List
1. 1080
2. 300
3. 8
4. 10
5. 1
6. 8748
7. 27
8. 504
9. 71
10. 8
11. 38
12. 1936
13. 10
14. 50
15. 34220
16. 32
17. 6029
18. 2112
19. 6034
20. 95004
21. 48
22. 8
23. 38
24. 30
25. 2
National Average Statistics
SMO (Open) Previous Years' Cut-off Points (Inclusive of Round 2 scores)
2010 Gold (38), Silver (9), Bronze (6), HM (5)
2009 Gold (27-29), Silver (9), Bronze (6), HM (5)
2008 Gold (27), Silver (11), Bronze (10), HM (6)
2007 Gold (19-20), Silver (9), Bronze (6), HM (5)
Update:
2011 Gold (18), Silver (9), Bronze (6), HM (5) Cut-off for Round 2: 9
My Score: 23+50
12 comments:
aiyahyahyah i put 720 for first qn
how come number one not 720
Because the frame of reference is also rotating
If the two coins are perpendicular to each other, may the answer be 720?
for first question you have to remember that it is not on a flat plane but a 360 degrees arch (in other words a circle) so you have to add 360 degrees to whatever answer obtained if the coin is rolling on a flat plane
For question 22, isn't the answer 9 instead of 8? My combination was 1!+2!+3!=3^3 And therefore x+y+z=3+3+3=9.
To Anonymous above,
1!+2!+3!=9 but 3^3=27 they are not equal. It is 3^2.
x+y+z=3+3+2=8
Lim Min
Some of the solutions of the SMO (open) section can be seen at:
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=150&t=409741&p=2300694#p2300694
Qn 1.
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=47&t=416050
Qn 2.
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=42&t=416051
Qn 3.
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=52&t=416052
Qn 4.
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=57&t=416053
Qn 5.
http://www.artofproblemsolving.com/Forum/viewtopic.php?f=57&t=416054
This paper is retarded
Erm so for qn 2 if we look the distance wouldnt change if we shifted it from 300 to 200 hundred right? the question asked for the minimum distance travelled in toal and 100*200+200*0+300*100=100*300+200*100+300*0=50,000?
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